Friday 2 October 2015

NON PERFECT SQUARE EXAMPLES

NON PERFECT SQUARE EXAMPLES

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READ MORE:
http://www.sapnaedu.in/how-to-obtain-the-square-root-of-imperfect-square/
https://www.youtube.com/watch?v=z7dZxUsv2tU
https://www.youtube.com/watch?v=gNcdQ42zwe4
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HOW TO OBTAIN THE SQUARE ROOT OF IMPERFECT SQUARE ?

FAST MATHS TRICK: : HOW TO CHECK WHETHER THE GIVEN NUMBER IS A PERFECT SQUARE OR NOT - HINDIHTTPS://WWW.YOUTUBE.COM/WATCH?V=VQ5MIDA_8WG





You might have come across a number of questions in the competitive examinations, where you need to find a square root of a number. We have already discussed the shortcut on obtaining the square root of a number, if the number is a perfect square.
If the number is an imperfect square however, the conventional method is to go for division technique to obtain the square root of a number. However this technique takes a long time.
In this tutorial, we will discuss a  shortcut to obtain the approximate square root of an imperfect square.
Let’s say we need to calculate the square root of 95.

Square_Root_of_a_numbers_1

Let’s understand the steps:
Step 1 :  By looking at the number itself, we can guess, the square root of 95 lies between 9 and 10.
So, √95=9.__
Step 2 :  95 is 14 more than 92.  Add 14 divided by twice the integer part of the square root i.e., 9×2 = 18.

Square_Root_of_a_numbers1

So, the approximate square root of 95 is 9.77 which is very close to 9.747 which is the actual square-root of 95.

Consider another example, Let’s say we need to calculate the square root of 150.

Square_Root_of_a_numbers_4

Step 1 :  The square root of 150 lies between 12 and 13.
So, √150=12.__
Step 2 :  150 is 6 more than 122.  Add 6 divided by twice the integer part of the square root i.e., 12×2 = 24.

Square_Root_of_a_numbers_3

So, the approximate square root of 150 is 12.25 which is very close to 12.247 which is the actual square-root of 150.





Finding square roots of numbers that aren't perfect squares without a calculator


There are a number of ways to calculate square roots without a calculator. Here is guess and divide method.

Step–1: Estimate/find a perfect square root as close as possible to your number.
Step–2: Divide your number by the square root.
Step–3: Calculate the average of the result of step 2 and the root.
Step–4: Use the result of step 3 to repeat steps 2 and 3 until you have a number that is accurate enough for you.

Calculate the square root of 10 ( 10) to 4 decimal places.

1.    Find the perfect square number closer to 10. 32 = 9 and 42 = 16, so take 3.
2.    Divide 10 by 3. 10÷3 = 3.33 (you can round off the answer)
3.    Average 3.33 and 3. (3.33 + 3)÷2 = 3.1667

Repeat step 2: 10÷3.1667 = 3.1579
Repeat step 3: Average 3.1579 and 3.1667.
(3.1579 + 3.1667)÷2 = 3.1623

Try the answer --> Is 3.1623 squared equal to 10? 3.1623 x 3.1623 = 10.0001

If this is accurate enough for you, you can stop! Otherwise, you can repeat steps 2 and 3.

Finding-square-roots-without-calculatorHere's another example, 695 =?
  1.  Let us first guess for the root as 25.
  2. 695 ÷ 25 = 27.8
  3. (25 + 27.8) ÷ 2 = 26.4
  4. 695 ÷ 26.4 = 26.3257
  5. (26.4 + 26.3257) ÷ 2 = 26.36285
  6. 695 ÷ 26.36285 = 26.3628553

Last two findings are about equal, so you now have a good estimate of the root of 695. You can keep going through the process until you are satisfied with the accuracy.

So, √24.6=?

  1. Let's try 5 since 52 = 25, which is pretty close to 24.6.
  2. Divide 24.6 by 5. 24.6 ÷ 5 = 4.92
  3. (5 + 4.92) ÷ 2 = 4.96
You can stop here. 4.96 is pretty close to 4.9598 which is the actual square root of 24.6. Repeat steps 2 and 3 to any desired level of accuracy. The further you go, the harder the long division becomes. But the first few cycles yield a pretty close answer.
  • 24.6 / 4.96 = 4.9596
  • (4.96 + 4.9596) ÷ 2 = 4.9598

Some more examples solved concisely,

2613 =?
2500 = 50
2613 ÷ 50 = 52.26
(52.26 + 50) ÷ 2 = 51.13 (approx. answer)

√6673 =?
√6400 = 80
6673 ÷ 80 = 83.41
(83.41 + 80) ÷ 2 = 81.70 (approx. answer)

√89108 =?
√9,00,00 = 300
89108 ÷ 300 = 297.03
(297.03 + 300) ÷ 2 = 298.51 (approx. answer)

Another similar and easy way to approximate the square root of a number is to use the following equation:


The closer the known square is to the unknown, the more accurate the approximation. For instance, to estimate the square root of 15, we could start with the knowledge that the nearest perfect square is 16 (42).


So we've estimated the square root of 15 to be 3.875. The actual square root of 15 is 3.872983...

How to find square root of a number ( Prime factorization method) - Squares and square roots

http://www.cbsetuts.com/number-system/finding-square-root-of-a-perfect-square-by-prime-factorization/
https://www.youtube.com/watch?v=xqj7h9A5BS4


Square Root Of A Perfect Square By Prime Factorization :

In order to find the square root of a perfect square by prime factorization, follow the following steps.
Step I- Obtain the given number.
Step II- Resolve the given number into prime factors by successive division.
Step III- Make pairs of prime factors such that both the factors in each pair are equal. Since the number is a perfect square, you will be able to make an exact number of pairs of prime factors.
Step IV- Take one factor from each pair.
Step V- Find the product of factors obtained in step IV.
Step VI- The product obtained in step V is the required square root.

Illustrative Examples :
Square-Root-of-a-Perfect-Square-by-Prime-Factorization-example-1Example 1 : Find the square root of 576.
Solution : By prime factorization,
we get 576=(2 x 2) x (2 x 2) x (2 x 2) x (3 x 3)                            [ Make pairs of factors]
     \therefore     \sqrt { 576 }  = 2x2x2x3 = 24     [ Pickup one factor from each pair ] 



Square-Root-of-a-Perfect-Square-by-Prime-Factorization-example-2Example 2: Find the square root of  \sqrt { 7744 }
Solution: Step 1. Split the given number into prime factors.
                        7744 =2x2x2x2x2x2x11x11
                    Step 2. Form pairs of like factors.
                        7744 =(2×2)x(2×2)x(2×2)x(11×11)
                   

Step 3. From each pair. pick out one prime factor
                             1st pair              2nd pair           3rd pair            4th pair                              (2×2)       x            (2×2)          x     (2×2)           x      (11×11)
                             Pick out                Pick out              Pick out               Pick out
                               one 2                    one 2                    one 2                     one 2  
                  Step 4. Multiply the factors so picked.
                           The product is the square root of the given number.
                                       \sqrt { 7744}  =2x2x2x11 = 88.


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